In natural viewing, there can never be greater uncrossed disparities than the disparities created by light rays that are parallel to one another (i.e., coming from infinite distance). Because the corresponding points above fixation have uncrossed disparity, there is a fixation distance beyond which those points could never be stimulated by the natural environment. We calculated these critical fixation distances for each retinal eccentricity. In the left panel of
Figure 16, a binocular observer fixates a point in the head's mid‐sagittal plane at distance
Z 0 while a point at distance
Z 1 stimulates the retina at locations
α L and
α R relative to the foveae. The horizontal disparity due to
Z 1 is the difference in those locations. The horizontal disparity in radians is given by
where
I is the inter-ocular separation (Held, Cooper, O'Brien, & Banks,
2010). Rearranging, we obtain
This is the object distance that is associated with a given disparity and fixation distance. Those distances are plotted in the right panel of
Figure 16. Blue and red curves correspond to combinations of fixation distances (
Z 0) and object distances (
Z 1) for positive (uncrossed) disparities and negative (crossed) disparities, respectively; the disparities have been converted to degrees. For each positive disparity, there is a greatest fixation distance
Z 0 at which it is possible for that disparity to arise from the natural environment. That greatest distance is
I/
δ (
Equation 5 for
Z 1 = ∞). For disparities of +0.1° and +1.0°, the greatest fixation distances are 34.4 and 3.44 m, respectively (indicated by arrows in the figure). Greater distances could not possibly give rise to the observed disparity.